Mathematics Notes for 9th Class Exercise 6.1
“Math” a compulsory subject for 9th class Science students. and Mathematics Notes for 9th Class Exercise 6.1 or Math Notes Class 9 English Medium (Science Group) included in this book.
The Question is How to Finding H.C.F. ?
We can find H. C. F. of given expressions by the following two methods.
(i) By Factorization (ii) By Division
Sometimes it is difficult to find factors of given expressions. In that case, method of division can be used to find H. C. F. We consider some examples to explain these two methods.
(i) H.C.F. by Factorization
Example: Find the H. C. F. of the following polynomials. x2 – 4, x2 + 4x + 4, 2×2 + x – 6
Solution by factorization:
x2 – 4 = (x + 2) (x – 2)
x2 + 4x + 4 = (x + 2)2
2×2 + x – 6 = 2×2 + 4x – 3x – 6 = 2x(x + 2) – 3(x + 2)
= (x + 2) (2x – 3)
Hence, H. C. F. = x + 2
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Math Solution 9th Class (Science Group)
Chapter 06 - ALGEBRAIC MANIPULATION
Chapter 07 - LINEAR EQUATIONS AND INEQUALITIES
Chapter 08 - LINEAR GRAPHS & THEIR APPLICATION
Chapter 14 - RATIO AND PROPORTION
Chapter 15 - PYTHAGORAS’ THEOREM
Chapter 16 - THEOREMS RELATED WITH AREA
Math Text Books
9th Math Science Group (English Medium)
9th Math Science Group (Urdu Medium)
9th Math Arts Group (Urdu Medium)
Other Math Notes
10th Class Math Science Group (English Medium)
10th Class Math Science Group (Urdu Medium)
10th Math Past Papers (Science Group)
10th Math Past Papers (Arts Group)
9th Class Math Science Group (English Medium)
9th Class Math Science Group (Urdu Medium)
9th Class Math Arts Group (Urdu Medium)
9th Class Math Past Papers (Science Group)
9th Class Math Past Papers (Arts Group)
Mathematics Notes for 9th:
How to find L.C.M. by Factorization:
Working Rule to find L.C.M. of given Algebraic Expressions
(i) Factorize the given expressions completely i.e., to simplest form.
(ii) Then the L.C.M. is obtained by taking the product of each factor appearing in any of the given expressions, raised to the highest power with which that factor appears.
Example: Find the L.C.M. of p(x) = 12(x3 – y3) and q(x) = 8(x3 – xy2)
Solution: By prime factorization of the given expressions, we have
p(x) = 12(x3 – y3) = 22 x 3 x (x – y) (x2 + xy + y2)
and q(x) = 8(x3 – xy2) = 8x(x2 – y2) = 23x(x + y) (x – y)
Hence L.C.M. of p(x) and q(x),
23 x 3 x x(x + y) (x – y) (x2 + xy + y2) = 24x (x + y) (x3 – y3)
There are Seventeen chapters in Mathematics 9th Class for Punjab Textbook Board, Lahore. Solutions of all the chapters are given below. Anyone can download the PDF file of the notes. Note that, you can view these notes only if you have PDF reader software/ App on your device. However online view of the notes is also available on eStudent.pk . You can find all solution along with 9th Class Math Notes in Urdu (Science Group), Math MCQs Class 9.
Math Notes Class 9:
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